Hello Readers,

If you want to solve problems related to

Q4. Two trucks travel the same distance at the speed of 50 kmph and 60 kmph. Find the distance when the distance when the time taken by both trucks has a difference of 1 hour?If you want to solve problems related to

**Time and Distance using tricks**, this post is for you. Here, please note that we are not providing you the tricks of**Boats & Streams**in this post. This post only cover the tricks related to**Time and Distance.**

__Shortcut Tricks on Time and Distance__**Speed -**we can define speed as the distance covered by an object in unit time.

**How to convert km/h into m/s?**

In order to convert any quantity from

**km/h**to**m/s**, just multiply the given quantity with (5/18).**How to convert m/s into m/s?**
For converting any given quantity from

**m/s**to**km/h**, just multiply the given quantity with (18/5).

**Tricks for solving Some Typical Question****Type-1 :**If some distance is travelled at x km/hr and the same distance is travelled at y km/hr then the average speed during the whole journey is given by:

**Type-2:**If a person travels a certain distance at x km/hr and returns at y km/hr, if the time taken to the whole journey is T hours then the one way distance is given by

**Type-3:**If two persons A and B start their journey at the same time from two points P and Q towards each other and after crossing each other they take

**a**and

**b**hours in reaching Q and P respectively, the

**Type-4:**If the same distance is covered at two different speeds S

_{1}and S

_{2}and the time taken to cover the distance are T

_{1}and T

_{2}, then the distance is given by

**Questions for Practice**

Q1. John goes from his home to school at the speed of 2 km/hr and returns at the speed of 3 km/hr. What is his average speed during whole journey in m/sec?

- .57 m/sec
- 2.4m/sec
- .67 m/sec
- .64 m/sec

- 12 km
- 14 km
- 18 km
- 16 km

- 10 km/hr
- 12 km/hr
- 16 km/hr
- 18 km/hr

- 200 km
- 300 km
- 250 km
- 400 km

**Answers along with Explanation**

- (3) Let’s say x = 2 km/hrAnd y = 3 km/hr, so

Now, average speed in m/sec= 2.4*(5/18) = .67m/sec - (3) Let’s say x = 10 km/hry = 10 km/hr, andT = 3 hrs, then

So the distance between home and market is 18 km. - (1) Let’s say A = Ram and B = Lakhana = 1 and b = 4, then

(20/Lakhan speed) = (2/1)Lakhan’s Speed = 10 km/hr - (2)Let’s say S
_{1}= 50 kmph,S_{2}= 60 kmphT_{1}– T_{2}= 1

Distance = [(50*60)/(60-50)]*1 = 300km

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